◦	NAME: FIAKA IFEANYICHUKWU 
	◦	COURSE:MATH 204
	◦	DEPARTMENT:COMPUTER SCIENCE
	◦	MATRIC NO:18/SCI01/034


	◦	1        2         8
	◦	4        7         6
	◦	9        5         3
	◦	QUESTION 1
	◦	i.

	◦	|X|=
 
 
	◦	|X|= 1(21 - 30) – 2(12 - 54) + 8(20 - 63)
	◦	|X|= -9 + 84 – 344 = - 269
	◦	|X|NOT EQUAL TO 0, Therefore, Matrix X is a Non-Singular matrix
 
	◦	ii.
	◦	0        5         0
	◦	-3     - 7        -1
	◦	2        1         9

	◦	|Y|=
 
 
	◦	|Y|= 0(171 + 1) – 5(-27 + 2) + 0(-3 + 14)
	◦	|Y|= 0 + 125 – 0 = 125
	◦	|Y|NOT EQUAL TO  0, Therefore, Matrix Y is a Non-Singular matrix
 
	◦	iii.
	◦	0        5         0
	◦	-3     - 7        -1
	◦	2        1         9

	◦	RANK OF Y
	◦	|Y|=
 
 
	◦	|Y|= 0(171 + 1) – 5(-27 + 2) + 0(-3 + 14)
	◦	|Y|= 0 + 125 – 0 = 125 IT IS NOT EQUAL TO 0; HENCE THE RANK OF Y IS 3
 
	◦	1        7         8
	◦	1         0        5
	◦	11       6      12
 
	◦	iv.

	◦	|X+Y|=
 
 
	◦	|X+Y|= 1(0 - 30) – 7(12 - 55) + 8(6 - 0)
	◦	|X+Y|= -30 + 301 + 48 = 319
	◦	|X+Y|NOT EQUAL TO 0, Therefore, Matrix X+Y is a Non-Singular matrix
	◦	v.
	◦	0       25         0
	◦	-15    -35     -5
	◦	10       5      45

	◦	|5Y|=
 
 
	◦	|5Y|= 0(-1575 + 25) – 25(-675 + 50) + 0(-75 + 350)
	◦	|5Y|= -0 + 15625 – 0 = 15625
	◦	|5Y|NOT EQUAL TO 0, Therefore, Matrix 5Y is a Non-Singular matrix
 
	◦	QUESTION 2
	◦	T(m)= 1
	◦	T(h)= 1
	◦	T(i)= 3
	◦	T(k)= 5
	◦	T(o)= 9
	◦	T(r)= 9